SELECT department_id, last_name, salary, RANK() OVER (PARTITION BY department_id ORDER BY salary DESC) AS rank, DENSE_RANK() OVER (PARTITION BY department_id ORDER BY salary DESC) AS dense_rank, ROW_NUMBER() OVER (PARTITION BY department_id ORDER BY salary DESC) AS row_num FROM employees WHERE department_id IS NOT NULL ORDER BY department_id, salary DESC; Find the salary difference between each employee and the next highest paid employee in the same department.
SELECT product_id, product_name, list_price FROM oe.product_information WHERE list_price BETWEEN 50 AND 200 AND UPPER(product_name) NOT LIKE '%MONITOR%'; Problem 3: Show the department name, city, and the number of employees working in that department. Include departments with zero employees. oracle 12c sql hands-on assignments solutions
SELECT first_name, last_name, hire_date, TRUNC(MONTHS_BETWEEN(SYSDATE, hire_date) / 12) AS years, TRUNC(MOD(MONTHS_BETWEEN(SYSDATE, hire_date), 12)) AS months, TRUNC(MONTHS_BETWEEN(SYSDATE, hire_date) / 12) || ' years, ' || TRUNC(MOD(MONTHS_BETWEEN(SYSDATE, hire_date), 12)) || ' months' AS tenure FROM employees; Mask email addresses for a report (Show first 2 letters, then ' ** ', then the domain 'oracle.com'). hire_date) / 12) AS years