[ \varepsilon_\textreff = \frac4.4+12 + \frac4.4-12\left(1+12\frac1.637.3\right)^-0.5 \approx 4.18 ]
[ W = \frac3e82(2.45e9)\sqrt\frac4.4+12 \approx 37.3 \text mm ]
(using simpler formula for demonstration) [ R_\textin(0) \approx 90\frac4.4^24.4-1\left(\frac28.437.3\right)^2 \approx 90\times\frac19.363.4\times0.58 \approx 297\ \Omega ]
To match the feed line impedance ( Z_0 ) (e.g., 50 Ω): [ Z_0 = R_\textin(0) \cos^2\left(\frac\piLy_0\right) ] [ y_0 = \fracL\pi \cos^-1\sqrt\fracZ_0R_\textin(0) ]
[ \Delta L = 0.412 \times 1.6 \frac(4.18+0.3)(37.3/1.6+0.264)(4.18-0.258)(37.3/1.6+0.8) \approx 0.74 \text mm ]
If ( R_\textin(0) ) is not known from the exact formula, use the approximation: [ R_\textin(0) \approx 90\frac\varepsilon_r^2\varepsilon_r - 1\left(\fracLW\right)^2 \quad (\textfor thin substrates) ] Given: ( f_r = 2.45 \text GHz ) ( \varepsilon_r = 4.4 ) (FR4) ( h = 1.6 \text mm ) ( Z_0 = 50\ \Omega )
The input resistance from the edge (inset depth) is: [ R_\textin(y=y_0) = R_\textin(0) \cos^2\left(\frac\piLy_0\right) ]
[ L = \frac3e82\times2.45e9\sqrt4.18 - 2\times0.00074 \approx 28.4 - 0.00148 \approx 28.4 \text mm ]