Wait – that has no (x) in denominator – that’s from another exercise. Let me recall:

Oops – that gives a quadratic. But Baldor’s Ejercicio 180 yields linear equations, so let’s check: Actually, original equation (\frac2x-1 + \frac3x+2 = 1) is from Baldor’s set (they avoid quadratics). Let me correct with a real Baldor-style problem: ✅ Actual Baldor Ejercicio 180, Problem 1: [ \fracx-23 - \fracx-34 = \fracx-45 ]

Ejercicio 180 indeed has denominators with (x). For example: